100=16t^2+t+100

Solution for 100=16t^2+t+100 equation:

100=16t^2+t+100

We move all terms to the left:

100-(16t^2+t+100)=0

We get rid of parentheses

-16t^2-t-100+100=0

We add all the numbers together, and all the variables

-16t^2-1t=0

a = -16; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-16)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-16}=\frac{0}{-32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-16}=\frac{2}{-32}
=-1/16
$